
python - How do I clone a list so that it doesn't change unexpectedly ...
4150 new_list = my_list doesn't actually create a second list. The assignment just copies the reference to the list, not the actual list, so both new_list and my_list refer to the same list after the assignment. …
python - What is the best way to copy a list? - Stack Overflow
Feb 13, 2014 · So, is the only way to get a deepcopy of a list by using the copy module? Seems strange that Python doesn't include deep copy in its standard functionality.
python - How to deep copy a list? - Stack Overflow
import copy copy.copy() copy.deepcopy() copy() is a shallow copy function. If the given argument is a compound data structure, for instance a list, then Python will create another object of the same type …
Copying nested lists in Python - Stack Overflow
When we create copy, address reference for list a & b will be changed as in python everything is pass by reference. However, address of the items in the list will remain the same.
Python copy a list of lists - Stack Overflow
Feb 24, 2015 · When you call regular copy.copy() you are performing a shallow copy. This means that in a case of a list-of-lists, you will get a new copy of the outer list, but it will contain the original inner …
python - How to make a copy of a list of objects not change when ...
Jul 9, 2011 · Possible Duplicates: How to clone a list in python? What is the best way to copy a list in Python?
python - What is the difference between shallow copy, deepcopy and ...
May 6, 2017 · Normal assignment operations will simply point the new variable towards the existing object. The docs explain the difference between shallow and deep copies: The difference between …
python: changes to my copy variable affect the original variable
Nov 13, 2013 · I've got a list that I create a copy of in order to do some manipulations while still keeping the original list. However, when I set copy_list equal to org_list, they become the same thing, and if I …
Slicing a list in Python without generating a copy
Given a list of integers L, I need to generate all of the sublists L[k:] for k in [0, len(L) - 1], without generating copies. How do I accomplish this in Python? With a buffer object somehow?
python - Copy a list of list by value and not reference - Stack Overflow
49 Because python passes lists by reference This means that when you write "b=a" you're saying that a and b are the same object, and that when you change b you change also a, and viceversa A way to …